70b^2-32b-6=0

Solution for 70b^2-32b-6=0 equation:

70b^2-32b-6=0

a = 70; b = -32; c = -6;
Δ = b2-4ac
Δ = -322-4·70·(-6)
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2704}=52$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-52}{2*70}=\frac{-20}{140}
=-1/7
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+52}{2*70}=\frac{84}{140}
=3/5
$